oracle 更改账号密码Oracle分组取第一条数据

看看以前的私密日志,原来自己之前被很多小而简单的问题困惑过!

看着那时候我们还是新手中的新手做的备忘笔记!

其实就是用了Oracle的统计函数而已!

以前的日记(看样子应该是以前公司的源码,呵呵……)如下:勿喷!

对多数据进行分组排序后取每组第一条记录:

SELECT *  FROM (       SELECT ROW_NUMBER() OVER(       PARTITION BY  ZA40011_3.URIAGE_DENPYO_NO,ZA40011_3.URIAGE_DENPYO_ROW_NO         ORDER BY  ZA40011_3.KAKUTEI_SURYO_CS,                  ZA40011_3.KAKUTEI_SURYO_BL,                  ZA40011_3.KAKUTEI_SURYO_BT,                  ZA40011_3.SYUKKA_SHIJI_NO,                  ZA40011_3.SYUKKA_SHIJI_ROW_NO  DESC) LEV,                ZA40011_3 .*       FROM  WT_001_ZA40011_22070_2 ZA40011_2,             WT_001_ZA40011_22070_3 ZA40011_3,             JT_GYOMU_URIAGE_DETAIL URIAGE_DETAIL       WHERE        ZA40011_2.KAISYA_CODE = URIAGE_DETAIL.KAISYA_CODE           AND ZA40011_2.URIAGE_DENPYO_NO = URIAGEoracle账号_DETAIL.URIAGE_DENPYO_NO           AND ZA40011_2.URIAGE_DENPYO_ROW_NO = URIAGE_DETAIL.ROW_NO           AND URIAGE_DETAIL.KAISYA_CODE = ZA40011_3.KAISYA_CODE           AND URIAGE_DETAIL.URIAGE_DENPYO_NO = ZA40011_3.URIAGE_DENPYO_NO           AND URIAGE_DETAIL.ROW_NO = ZA40011_3.URIAGE_DENPYO_ROW_NO           AND ZA40011_3.KEPPIN_RIYU_CODE IS NOT NULL        ) WHERE LEV = 1-- ORDER BY KAKUTEI_SURYO_CS DESC
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